The O'ahu Interscholastic Association Red representatives for the league's 10-team tournament are set, but the order of the East's third through fifth seeds will be determined Saturday night.

The Farrington-Moanalua game at Roosevelt is the final piece of the playoff puzzle.

If Moanalua (3-2) wins, it will be the division's third seed with Castle (3-3) fourth and Farrington (2-3) fifth.

Moanalua became 3-2 when Roosevelt (2-4) forfeited its 16-0 win last week for using an ineligible player, it was reported earlier by ScoringLive.

If Farrington wins, then it, along with Moanalua and Castle will be in a three-way tie for third, all at 3-3. In this scenario, one would've beaten one, but not the other in the head-to-head tie-breaker. The next tie-breaker is record against common opponents (everyone played the same opponents in this case). Castle's win against Kailua last week would make the Knights the third seed. Farrington would be fourth and Moanalua fifth by the head-to-head tie-breaker. (Farrington and Moanalua both lost to Kailua.)

Kahuku (6-0) and Kailua (4-2) are the top two seeds. Kailua beat Moanalua so the Surfriders have the head-to-head tie-breaker if Na Menehune also finishes 4-2.

In the Red West, Saturday's Mililani-Leilehua winner will be the division's top seed with the loser being the second seed. The Mules are 5-0 and the Trojans are 4-1.

The rest of the Red's playoff seeds are set: Wai'anae (3-3) is third, Radford (3-3) is fourth and 'Aiea (2-4) is fifth. The Seariders beat the Rams Friday to win the head-to-head tie-breaker. Na Ali'i beat Campbell (also 2-4) Friday and won the head-to-head tie-breaker for fifth.

The first-round of the OIA Red tournament starts the weekend of Oct. 15-16 with the fourth and fifth seeds from opposite divisions playing each other. The top three seeds have first-round byes.

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